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Question: 1 / 400

What is the result of (7/5) raised to the power of -1?

(5/7)^1

To determine the result of raising \( \frac{7}{5} \) to the power of -1, it's important to understand the concept of negative exponents. A negative exponent indicates the reciprocal of the base raised to the opposite (positive) exponent.

When we have \( \left( \frac{7}{5} \right)^{-1} \), it translates to the reciprocal of \( \frac{7}{5} \), which is calculated as follows:

\[

\left( \frac{7}{5} \right)^{-1} = \frac{1}{\frac{7}{5}} = \frac{5}{7}

\]

Thus, \( \left( \frac{7}{5} \right)^{-1} \) simplifies to \( \frac{5}{7} \), which can also be expressed as \( \left( \frac{5}{7} \right)^1 \).

Choosing the correct option, we find that the answer corresponds to the form of the result, which is indeed \( \left( \frac{5}{7} \right)^1 \). This demonstrates that understanding negative exponents and their relationship to reciprocals is key in arriving

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(7/5)^1

(7/5)^-1

(5/7)^-1

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